wf_filter gives 'Called id for nil,' error

[anu-vaid]

Tried to use will_filter but cannot get it to work.

Called id for nil, which would mistakenly be 4 -- if you really wanted the id of nil, use object_id
Extracted source (around line #2):

1: <div style="margin:0;padding:0;display:inline">
2:   <%= hidden_field_tag(:wf_id, wf_filter.id) %>

1. I did all steps as outlined in the doc.
2. Since I am also using will_paginate, to avoid conflict, I added this to config/initializers/kaminari.rb

Kaminari.configure do |config|
config.page_method_name = :per_page_kaminari

if defined?(WillPaginate)
module WillPaginate
module ActiveRecord
module RelationMethods
def per(value = nil) per_page(value) end
def total_count() count end
end
end
module CollectionMethods
alias_method :num_pages, :total_pages
end
end
end
end

[berk]

Where are you getting this error? Is it from your code or from will_filter
partials?

wf_filter is not really exposed this way - it is injected into the
collection model that was filtered. For example,
if you did in the controller:

@users = User.filter(:params => params)

then you can access will filter:

@users.wf_filter.id

Can you show me a full example of what you do?

On Thu, Jul 19, 2012 at 10:55 AM, anu-vaid <
reply@reply.github.com

wrote:

Tried to use will_filter but cannot get it to work.

Called id for nil, which would mistakenly be 4 -- if you really wanted

the id of nil, use object_id
Extracted source (around line #2):

1: <div style="margin:0;padding:0;display:inline">
2:   <%= hidden_field_tag(:wf_id, wf_filter.id) %>

1. I did all steps as outlined in the doc.
2. Since I am also using will_paginate, to avoid conflict, I added this to
   config/initializers/kaminari.rb

Kaminari.configure do |config|
config.page_method_name = :per_page_kaminari

if defined?(WillPaginate)
module WillPaginate
module ActiveRecord
module RelationMethods
def per(value = nil) per_page(value) end
def total_count() count end
end
end
module CollectionMethods
alias_method :num_pages, :total_pages
end
end
end
end

---

Reply to this email directly or view it on GitHub:
#28

[anu-vaid]

Thanks for the quick response. Here's what I did

1. In gemfile

gem "will_filter"
gem "kaminari"

1. bundle install
2. rails generate "will_filter"
   rake db: migrate
3. In routes file

MyApp::Application.routes.draw do
mount WillFilter::Engine => "/will_filter

1. In controller

class UsersController < ApplicationController

def index
@users = User.filter(:params => params)
end

end

1. In view
   <%= will_filter_tag(@users) %>

I got an undefined method 'per' error. Read some and realized kaminari is conflicting with will_paginate so added

1. In config/initializers/kaminari.rb

   Kaminari.configure do |config|
   config.page_method_name = :per_page_kaminari

   if defined?(WillPaginate)
   module WillPaginate
   module ActiveRecord
   module RelationMethods
   def per(value = nil) per_page(value) end
   def total_count() count end
   end
   end
   module CollectionMethods
   alias_method :num_pages, :total_pages
   end
   end
   end
   end

and then I get

Called id for nil, which would mistakenly be 4 -- if you really wanted
the id of nil, use object_id
Extracted source (around line #2):

1:

2: <%= hidden_field_tag(:wf_id, wf_filter.id) %>

when I try and go to /companies/1/users

---

Anupama Vaid
www.parentsquare.com
805.637.8381

On Jul 19, 2012, at 11:25 AM, Michael Berkovich wrote:

Where are you getting this error? Is it from your code or from will_filter
partials?

wf_filter is not really exposed this way - it is injected into the
collection model that was filtered. For example,
if you did in the controller:

@users = User.filter(:params => params)

then you can access will filter:

@users.wf_filter.id

Can you show me a full example of what you do?

On Thu, Jul 19, 2012 at 10:55 AM, anu-vaid <
reply@reply.github.com

wrote:

Tried to use will_filter but cannot get it to work.

Called id for nil, which would mistakenly be 4 -- if you really wanted
the id of nil, use object_id
Extracted source (around line #2):

1:

2: <%= hidden_field_tag(:wf_id, wf_filter.id) %>

1. I did all steps as outlined in the doc.
2. Since I am also using will_paginate, to avoid conflict, I added this to
   config/initializers/kaminari.rb

Kaminari.configure do |config|
config.page_method_name = :per_page_kaminari

if defined?(WillPaginate)
module WillPaginate
module ActiveRecord
module RelationMethods
def per(value = nil) per_page(value) end
def total_count() count end
end
end
module CollectionMethods
alias_method :num_pages, :total_pages
end
end
end
end

---

Reply to this email directly or view it on GitHub:
#28

---

Reply to this email directly or view it on GitHub:
#28 (comment)

[aprilw]

I'm also seeing this issue when I go to [mysite]/tr8n/admin/language.

[frane]

I've tracked the problem down to these two lines (821,822) in /app/models/will_filter/filter.rb :

 recs = recs.page(page).per(per_page)
 recs.wf_filter = self

The problem occurs when trying to replace kaminari with will_paginate, as will_paginate returns an ActiveRecord::Relation instead of an Array.
A possible solution is to materialize the results (convert AR:Relation to Array) like so:

 recs = recs.page(page).per(per_page).to_a

However, it appears that a lot more work is necessary to replace kaminari with will_paginate as #8 suggests. Nevertheless it would be nice to have the option to chose between will_paginate and kaminari soon.