Added solution for Day2 Part2

Author: alexgibbs606

Day2/Part2.py

@@ -0,0 +1,84 @@
+from pathlib import Path
+
+from Day1.Part1 import _parse_elf_data
+
+def solve(file_path:Path) -> int:
+	''' Gives you the solution for the appropriate advent of code question.
+	Arguments:
+		file_path(pathlib.Path): The filepath in which to read data from.
+
+	Returns:
+		Answer for the appropriate advent of code questions.
+	'''
+	round_data = []
+	with open(file_path, 'r', encoding='UTF-8') as input_file:
+		round_data = input_file.readlines()
+
+	# Iterating through our rounds and finding the results
+	score_data = []
+	for round in round_data:
+		score_data.append(score_RPS(round))
+
+	return sum(score_data)
+
+def score_RPS(round_data) -> int:
+	''' Takes in a single game of rock paper scissors and returns the score.
+
+	This is for the second part of day2_2022, the second column is for what the result of the round should be.
+
+	Naming:
+		A: rock
+		B: paper
+		C: scissors
+
+		X: lose
+		Y: draw
+		Z: win
+
+	Scoring:
+		By Choice:
+			Rock: 1
+			Paper: 2
+			Scissors: 3
+		By outcome:
+			Win: 6
+			Draw: 3
+			Loss: 0
+
+	Arguments:
+		String representing two choices, your opponents and yours, split by a space.
+
+	Returns:
+		Integer representing number of point you would get for that round.
+	'''
+	''' See Day1 for ord and chr explanations.
+
+	We'll use the second column to make a key for calculating our choice score.
+	key = x:0 y:1 z:2, so second column - 87
+
+	Lets draw a table for points by choice, then think about our scores being 0 indexed, then mod 3 by adding 3 to everything
+	  A | B | C       A | B | C       A | B | C
+	X 3 | 1 | 2     x 2 | 0 | 1     x 2 | 3 | 4
+	Y 1 | 2 | 3     y 0 | 1 | 2     y 3 | 4 | 5
+	Z 2 | 3 | 1     z 1 | 2 | 0     z 4 | 5 | 6
+
+	So if we ordinate our first column (A-63=2), add the key from our second column, then mod 3, we have a 0 indexed score. Add 1 and we get our score.
+
+	Then using the key, can just multiply by 3 to get our win score.
+	x:loss:0
+	y:draw:3
+	z:win:6
+	'''
+	data = [ord(value) for value in round_data.strip().split(' ')]
+
+	# Creating our key with the second column and ord our first column
+	data[1] = data[1] - 88
+	data[0] = data[0] - 64
+
+	# Capturing our score
+	choice_score = ((data[0] + 1 + data[1]) % 3) + 1
+
+	# Now finding our status score
+	status_score = (data[1] * 3)
+
+	return status_score + choice_score

run.py

@@ -3,6 +3,6 @@
 
 
 
-from Day2 import Part1
+from Day2 import Part2
 
-print(Part1.solve(Path() / 'Day2' / 'input.txt'))
+print(Part2.solve(Path() / 'Day2' / 'input.txt'))