Added solution for Day2 Part1

Author: alexgibbs606

Day2/Part1.py

@@ -0,0 +1,115 @@
+from pathlib import Path
+from typing import List
+
+def solve(file_path:Path) -> int:
+	''' Gives you the sum of all your points for the given RPS file.
+	Arguments:
+		file_path(pathlib.Path): The filepath in which to read elf data from.
+
+	Returns:
+		Integer representing number of points if following the guide that is input_file
+	'''
+	return sum(get_RPS_scores(file_path))
+
+def get_RPS_scores(file_path:Path) -> List[int]:
+	''' Reads rock-paper-scissors plays from a file and returns the total "points"
+
+	Naming:
+		A, X: rock
+		B, Y: paper
+		C, Z: scissors
+
+	Scoring:
+		By Choice:
+			Rock: 1
+			Paper: 2
+			Scissors: 3
+		By outcome:
+			Win: 6
+			Draw: 3
+			Loss: 0
+
+	Arguments:
+		file_path(pathlib.Path): The filepath in which to read elf data from.
+
+	Returns:
+		List of integer representing number of points if following the guide that is input_file
+	'''
+
+	# Reading in our file and splitting on newlines
+	round_data = []
+	with open(file_path, 'r', encoding='UTF-8') as input_file:
+		round_data = input_file.readlines()
+
+	# Lets iterate through each of our rounds finding the results
+	score_data = []
+	for round in round_data:
+		score_data.append(score_RPS(round))
+
+	return score_data
+
+def score_RPS(round_data) -> int:
+	''' Takes in a single game of rock paper scissors and returns the score.
+
+	Naming:
+		A, X: rock
+		B, Y: paper
+		C, Z: scissors
+
+	Scoring:
+		By Choice:
+			Rock: 1
+			Paper: 2
+			Scissors: 3
+		By outcome:
+			Win: 6
+			Draw: 3
+			Loss: 0
+
+	Arguments:
+		String representing two choices, your opponents and yours, split by a space.
+
+	Returns:
+		Integer representing number of point you would get for that round.
+	'''
+	''' Making both answers the same value + 1
+
+	Alright, listen up
+
+	ord is a python function that turns alphabetical characters into ordinals.
+	chr reverses that
+
+	i.e. ord('X') is 88, ord('A') is 65
+	Here is a table for continence https://www.johndcook.com/ascii.png
+
+	Now lets talk about scoring. If we ordinate our answer and minus 87, we just get our score. i.e. ord('X') - 87 == 1.
+
+	Now lets talk about solving. To start (stay with me), we'll ordinate our vote, remove 23, then characterize. This results in our votes being in the same field as our opponents. i.e. rock = A, paper = B...
+	Dual is simple, if we match, we draw
+	To check for winning, we can simply check if ours is one higher or two lower
+		a - b (+1)
+		b - c (+1)
+		or
+		c - a (-2)
+	else this and we have our no win.
+	'''
+	score = 0
+	# Splitting and iterating our values
+	data = [ord(value) for value in round_data.strip().split(' ')]
+
+	# Alright, lets move our choice to the same as our opponents
+	data[1] = data[1] - 23
+
+	# Counting our score
+	score += data[1] - 64
+
+	# Checking for draw
+	if data[0] == data[1]:
+		return score + 3
+
+	# Checking for win
+	if data[1] in [data[0] + 1, data[0] - 2]:
+		return score + 6
+
+	# If we got here, we've lost, lets just return our score
+	return score

Day2/example.txt

@@ -0,0 +1,3 @@
+A Y
+B X
+C Z