Mary Tian CS Fun Bipartition Graph #49
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kyra-patton
reviewed
Jul 28, 2022
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| Time Complexity: ? | ||
| Space Complexity: ? |
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| if dislikes[0]: | ||
| start_node = 0 | ||
| else: | ||
| start_node = 1 |
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Consider the edge case where there are multiple disconnected nodes indexed at the beginning of dislikes
For example: `dislikes = [ [], [], [], [1,2] ]
How might you refactor your code to account for this edge case?
| visited.add(start_node) | ||
| red.add(start_node) | ||
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| while len(queue) != 0: |
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