Reverse a linked list from position m to n. Do it in one-pass.
Note: 1 ≤ m ≤ n ≤ length of list.
Example:
Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->2->5->NULL
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* reverseBetween(ListNode* head, int m, int n) {
if (!head || m < 1 || n < 1)
return head;
int cc = 1;
auto t = head;
ListNode *mp = nullptr, *np = nullptr, *tp = nullptr;
auto before = mp, after = np;
while (t && cc <= n) {
if (m == cc) {
mp = t;
before = tp;
}
if (n == cc) {
np = t;
after = t->next;
break;
}
tp = t;
t = t->next;
cc++;
}
if (!mp || !np) return head;
// reverse
ListNode* next = nullptr;
t = mp;
while (t) {
auto tn = t->next;
t->next = next;
if (t == np)
break;
next = t;
t = tn;
}
if (before) {
before->next = np;
}
mp->next = after;
return m > 1? head : np;
}
};