You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
// 0ms
class Solution {
public:
int climbStairs(int n) {
if (n < 2) return 1;
vector<int> v(n+1, 0);
v[0] = 0;
v[1] = 1;
v[2] = 2;
for (int i = 3; i <= n; i++) {
v[i] = v[i-1] + v[i-2];
}
return v[n];
}
};
// 0ms
class Solution {
public:
int climbStairs(int n) {
if (n < 2) return 1;
vector<int> v(n+1, 0);
v[n] = 1;
v[n-1] = 1;
for (int i = n-2; i >= 0; i--) {
v[i] = v[i+1] + v[i+2];
}
return v[0];
}
};