code

[nianxiongdi]

repeat

function repeat (func, times, wait) {
    return function(){
        var _arguments=arguments;
        var timer = setInterval(function(){
            func.apply(null,Array.prototype.slice.call(_arguments,0));
            --times || clearInterval(timer);
        }, wait);
    }
}

var repeatedFun = repeat(console.log, 10, 100);
repeatedFun("hellworld");



function repeat (func, times, wait) {
    return function(){
        var _arguments=arguments;
        var that=this;
        this.timer=function(_t){
            _t&&clearTimeout(_t);
            var t=setTimeout(function(){
                func.apply(null,Array.prototype.slice.call(_arguments,0));
                --times && that.timer(t);
            },wait);
        }
        this.timer();
    }
}

接口依次调用

 
有一个url数组
var urls = ['/a', '/b', '/c',...]
要求依次请求这几个url， 要求是 第一个请求完了才发第二个请求，第二个完了才发第三个请求
如此依次。

var url = [];
var count = 0;
function getData(url){
    if(count>=url.length) return;
    count++;
    Promise.resolve(jQuery.get(url[0])).then(function(data){
        console.log(data);
        getData(url.slice(1));
    });
}
 

webpack打包原理

• https://juejin.im/post/5ac9d8286fb9a028c97a5420#heading-10

• mini - https://blog.csdn.net/liuliuliu_666/article/details/78364791