First Argument in Function.prototype.call should be optional

[jonath92]

🕗 Version & Regression Information

Occurs in the latest Version (4.3.2) and nightly version

💻 Code

Function.prototype.call combined with Optional Chaining is a nice way to only call a method if the method is defined (see this thread).

foo?.call()

🙁 Actual behavior

Ts complains: Expected at least 1 arguments, but got 0

🙂 Expected behavior

I expect that this works as the first argument is actually optional according to Mozilla and own observations.

[MartinJohns]

Function.prototype.call combined with Optional Chaining is a nice way to only call a method if the method is defined

Am I missing something weird here? You can do that with the ?.() operator as well.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Optional_chaining#optional_chaining_with_function_calls

[jonath92]

I didn't know that. This is indeed much better as you don't loose IntelliSense that way. Thanks. But this is a Bug anyway (also not very important tbh) :-)

[MartinJohns]

It's not explicitly mentioned, but #27028 seems to me more like it's a design decision, not a bug. Calling .call() without a thisArg rarely makes sense, and in these few cases you can just pass undefined along.