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53_maximum_subarray.md

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Given an integer array nums, find the subarray with the largest sum, and return its sum.

Example 1:

Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: The subarray [4,-1,2,1] has the largest sum 6.

Example 2:

Input: nums = [1]
Output: 1
Explanation: The subarray [1] has the largest sum 1.

Example 3:

Input: nums = [5,4,-1,7,8]
Output: 23
Explanation: The subarray [5,4,-1,7,8] has the largest sum 23.

Solution

class Solution:
    def maxSubArray(self, nums: List[int]) -> int:
        best_sum = float('-inf')
        cur_sum = 0
        for n in nums:
            cur_sum = max(n, cur_sum + n)
            best_sum = max(best_sum, cur_sum)
        return best_sum