1507_reformat_date.md

Reformat Date

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

Solution

class Solution:
    def reformatDate(self, date: str) -> str:
        date = date.split()
        date[0] = date[0][:-2]
        date[0] = '0' + date[0] if len(date[0]) == 1 else date[0]
        months = {'Jan': '01',
                  'Feb': '02',
                  'Mar': '03',
                  'Apr': '04',
                  'May': '05',
                  'Jun': '06',
                  'Jul': '07',
                  'Aug': '08',
                  'Sep': '09',
                  'Oct': '10',
                  'Nov': '11',
                  'Dec': '12',}
        return f'{date[2]}-{months[date[1]]}-{date[0]}'