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lim[x->oo] sin(x) returns a number (the limit does not exist!) #74

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jackmaney opened this issue Nov 21, 2014 · 0 comments
Open

lim[x->oo] sin(x) returns a number (the limit does not exist!) #74

jackmaney opened this issue Nov 21, 2014 · 0 comments

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@jackmaney
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Hi guys,thank you for using Hilbert.
You need to execute "postulate zfc_analysis" if you wanna do real analysis.

Enjoy! -> postulate zfc_analysis
success! :)
Enjoy! -> lim[x->oo] sin(x)
0.03574879797201651

Since the set of x such that sin(x) == 1 and the set of x such that sin(x) == -1 are both unbounded, it follows that this limit cannot possibly exist.

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