How to force word-sized argument?

[boeckmann]

In rare cases one wants to generate a three byte-instruction while the assembler generates an optimized two-byte instruction.

lda 1      ; two-byte instruction, argument is of type byte
lda 1+0000 ; three-byte instruction, argument is of type word
lda [w]1   ; three-byte instruction, argument 0 is converted to word

The solution is to either add a zero of type word, or use the conversion operator [w]. A decimal number is of type word if it has four digits, so 0000 is of type word. Alternatively all hex values of three or more digits are considered of type word. So adding $000 yields the same result.

The code generated is

A5 01            lda 1
AD 01 00         lda 1+0000
AD 01 00         lda [w]1

[waltje]

Yes, this will kick in the inference typing.

…

--Fred On Tuesday, April 11, 2023 at 04:27:14 PM EDT, Bernd Böckmann ***@***.***> wrote: In rare cases one wants to generate a three byte-instruction while the assembler generates an optimized two-byte instruction. Some assemblers have a type cast operator or similar to force a byte argument to be of type word. ASM6502 has no special type cast feature but solves this problem in a different way: lda 1      ; two-byte instruction, argument is of type byte lda 1+0000 ; three-byte instruction, argument is of type word The solution is to add a zero of type word. A decimal number is of type word if it has four digits, so 0000 is of type word. — Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you are subscribed to this thread.Message ID: ***@***.***>