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Copy path373.FindKPairsWithSmallestSums.cpp
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373.FindKPairsWithSmallestSums.cpp
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/*
* @lc app=leetcode id=373 lang=cpp
*
* [373] Find K Pairs with Smallest Sums
*
* https://leetcode.com/problems/find-k-pairs-with-smallest-sums/description/
*
* algorithms
* Medium (37.65%)
* Likes: 1941
* Dislikes: 130
* Total Accepted: 127.9K
* Total Submissions: 335.1K
* Testcase Example: '[1,7,11]\n[2,4,6]\n3'
*
* You are given two integer arrays nums1 and nums2 sorted in ascending order
* and an integer k.
*
* Define a pair (u, v) which consists of one element from the first array and
* one element from the second array.
*
* Return the k pairs (u1, v1), (u2, v2), ..., (uk, vk) with the smallest
* sums.
*
*
* Example 1:
*
*
* Input: nums1 = [1,7,11], nums2 = [2,4,6], k = 3
* Output: [[1,2],[1,4],[1,6]]
* Explanation: The first 3 pairs are returned from the sequence:
* [1,2],[1,4],[1,6],[7,2],[7,4],[11,2],[7,6],[11,4],[11,6]
*
*
* Example 2:
*
*
* Input: nums1 = [1,1,2], nums2 = [1,2,3], k = 2
* Output: [[1,1],[1,1]]
* Explanation: The first 2 pairs are returned from the sequence:
* [1,1],[1,1],[1,2],[2,1],[1,2],[2,2],[1,3],[1,3],[2,3]
*
*
* Example 3:
*
*
* Input: nums1 = [1,2], nums2 = [3], k = 3
* Output: [[1,3],[2,3]]
* Explanation: All possible pairs are returned from the sequence:
* [1,3],[2,3]
*
*
*
* Constraints:
*
*
* 1 <= nums1.length, nums2.length <= 10^4
* -10^9 <= nums1[i], nums2[i] <= 10^9
* nums1 and nums2 both are sorted in ascending order.
* 1 <= k <= 1000
*
*
*/
// @lc code=start
#include <queue>
#include <vector>
class Solution {
public:
std::vector<std::vector<int>> kSmallestPairs(std::vector<int>& nums1,
std::vector<int>& nums2,
int k) {
auto comp = [](const std::vector<int>& lhs,
const std::vector<int>& rhs) {
return (lhs[0] + lhs[1]) < (rhs[0] + rhs[1]);
};
std::priority_queue<std::vector<int>, std::vector<std::vector<int>>,
decltype(comp)>
pq(comp);
for (auto n1 : nums1) {
for (auto n2 : nums2) {
pq.push({n1, n2});
if (pq.size() > k) {
pq.pop();
}
}
}
std::vector<std::vector<int>> ret;
while (!pq.empty()) {
ret.push_back(pq.top());
pq.pop();
}
return ret;
}
};
// @lc code=end