-
Notifications
You must be signed in to change notification settings - Fork 19.7k
/
Copy pathValidParentheses.java
59 lines (58 loc) · 1.96 KB
/
ValidParentheses.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
package com.thealgorithms.strings;
// Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine
// if the input string is valid. An input string is valid if: Open brackets must be closed by
// the same type of brackets. Open brackets must be closed in the correct order. Every close
// bracket has a corresponding open bracket of the same type.
public final class ValidParentheses {
private ValidParentheses() {
}
public static boolean isValid(String s) {
char[] stack = new char[s.length()];
int head = 0;
for (char c : s.toCharArray()) {
switch (c) {
case '{':
case '[':
case '(':
stack[head++] = c;
break;
case '}':
if (head == 0 || stack[--head] != '{') {
return false;
}
break;
case ')':
if (head == 0 || stack[--head] != '(') {
return false;
}
break;
case ']':
if (head == 0 || stack[--head] != '[') {
return false;
}
break;
default:
throw new IllegalArgumentException("Unexpected character: " + c);
}
}
return head == 0;
}
public static boolean isValidParentheses(String s) {
int i = -1;
char[] stack = new char[s.length()];
String openBrackets = "({[";
String closeBrackets = ")}]";
for (char ch : s.toCharArray()) {
if (openBrackets.indexOf(ch) != -1) {
stack[++i] = ch;
} else {
if (i >= 0 && openBrackets.indexOf(stack[i]) == closeBrackets.indexOf(ch)) {
i--;
} else {
return false;
}
}
}
return i == -1;
}
}