Using a function inside by causes troubles

[AbrJA]

I'm facing an issue when I summarize a data.table using a function inside the "by" clause

Here is an example:

> library(data.table)
> dt <- data.table(x = c(4, 5, 1, 3, 2), y = 1L, key = "x")
> dt
   x y
1: 1 1
2: 2 1
3: 3 1
4: 4 1
5: 5 1
> str(dt)
Classes ‘data.table’ and 'data.frame':	5 obs. of  2 variables:
 $ x: num  1 2 3 4 5
 $ y: int  1 1 1 1 1
 - attr(*, ".internal.selfref")=<externalptr> 
 - attr(*, "sorted")= chr "x"

> dt_sum <- dt[, .(.N), by = .(round(2 / x))]
> dt_sum
   round N
1:     2 1
2:     1 2
3:     0 2
> str(dt_sum)
Classes ‘data.table’ and 'data.frame':	3 obs. of  2 variables:
 $ round: num  2 1 0
 $ N    : int  1 2 2
 - attr(*, "sorted")= chr "round"
 - attr(*, ".internal.selfref")=<externalptr> 

> dt_sum[round == 0] # ERROR
Empty data.table (0 rows and 2 cols): round,N
> dt_sum[round == 1] # CORRECT
   round N
1:     1 2
> dt_sum[round == 2] # ERROR
Empty data.table (0 rows and 2 cols): round,N

I think the issue is here - attr(*, "sorted")= chr "round" because dt_sum isn't already sorted. I don't know if it's a known issue and there's documentation about it, I didn't find anything. Gretings!

> sessionInfo()
R version 4.2.2 (2022-10-31)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 20.04.5 LTS

Matrix products: default
BLAS:   /usr/lib/x86_64-linux-gnu/blas/libblas.so.3.9.0
LAPACK: /usr/lib/x86_64-linux-gnu/lapack/liblapack.so.3.9.0

locale:
 [1] LC_CTYPE=es_MX.UTF-8       LC_NUMERIC=C               LC_TIME=es_MX.UTF-8        LC_COLLATE=es_MX.UTF-8     LC_MONETARY=es_MX.UTF-8   
 [6] LC_MESSAGES=es_MX.UTF-8    LC_PAPER=es_MX.UTF-8       LC_NAME=C                  LC_ADDRESS=C               LC_TELEPHONE=C            
[11] LC_MEASUREMENT=es_MX.UTF-8 LC_IDENTIFICATION=C       

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base     

other attached packages:
[1] data.table_1.14.6

loaded via a namespace (and not attached):
[1] compiler_4.2.2 tools_4.2.2   

[jangorecki]

Thank you for the report. Is it reproducible on master branch? 1.14.6 is far behind master.

[ben-schwen]

Can reproduce on current master and is similar to #5361. At least the experienced problem is the same

AFAIR the fast subsetting problem always arises when a data.table has a key attribute although it isn't really sorted according to that key.

As already pointed out by @AbrJA, using x in by shouldn't automatically set the by column as key.

[AbrJA]

As a temporal solution (if someone is facing the same issue), using "keyby" instead of "by" solves the problem

> library(data.table)
> 
> dt <- data.table(x = c(4, 5, 1, 3, 2), y = 1L, key = "x")
> dt
   x y
1: 1 1
2: 2 1
3: 3 1
4: 4 1
5: 5 1
> str(dt)
Classes ‘data.table’ and 'data.frame':	5 obs. of  2 variables:
 $ x: num  1 2 3 4 5
 $ y: int  1 1 1 1 1
 - attr(*, ".internal.selfref")=<externalptr> 
 - attr(*, "sorted")= chr "x"

> dt_sum <- dt[, .(.N), keyby = .(round(2 / x))]
> dt_sum
   round N
1:     0 2
2:     1 2
3:     2 1
> str(dt_sum)
Classes ‘data.table’ and 'data.frame':	3 obs. of  2 variables:
 $ round: num  0 1 2
 $ N    : int  2 2 1
 - attr(*, "sorted")= chr "round"
 - attr(*, ".internal.selfref")=<externalptr> 

> dt_sum[round == 0]
   round N
1:     0 2
> dt_sum[round == 1]
   round N
1:     1 2
> dt_sum[round == 2]
   round N
1:     2 1

[MichaelChirico]

OK I think the key is the function has to return a strictly decreasing ordering of the key column -- not just any function in by= triggers the bug:

DT=data.table(a=-1:2, key='a')
key(DT[,.N, by=.(a2=a**2)])
# NULL

here a2 = c(1L, 0L, 4L).

That would mean this line is to blame, since a strictly decreasing input to forderv() returns a 0-length o__

data.table/R/data.table.R

Line 1538 in 70c64ac

bysameorder = orderedirows && !length(o__)

forderv(list(b=2:1), sort=FALSE, retGrp=TRUE)
# integer(0)
# attr(,"starts")
# [1] 1 2
# ... other attr...

@jangorecki is this possibly related to the forder change to re-use sorting? no, confirmed the same issue on 1.15.0

[MichaelChirico]

Some related faulty logic determining the key of the result:

DT=data.table(a=1:3, b=3:1, key='a,b')
key(DT[,.N, by=.(a^b, rep(1L, 3L))])
# [1] "a"   "rep"