uuid kwarg of Parameter() not available in qiskit 0.44

[aeddins-ibm]

Version: qiskit-ibm-provider 0.7.3

What is the current behavior?

Currently, the qiskit version in the qiskit-ibm-provider requirements.txt is 0.44.1:

qiskit-ibm-provider/requirements.txt

Line 1 in f85496e

qiskit>=0.44.1

In this version of qiskit (aka qiskit-terra 0.25), Parameter.__init__() does not have the kwarg uuid:
https://github.com/Qiskit/qiskit/blob/a9a41309427b56a7956b03ee67bda95ef8a89636/qiskit/circuit/parameter.py#L75

(not to be confused with Parameter.__new__(), which does have this kwarg, but is not relevant here AFAICT).

Howver, qiskit-ibm-provider passes the uuid kwarg to qiskit's Parameter.__init__() here:

qiskit-ibm-provider/qiskit_ibm_provider/qpy/binary_io/value.py

Line 215 in f85496e

param = Parameter(name, uuid=param_uuid)

This errors during deserialization when one tries to e.g. load a job result.

I was able to resolve this issue locally by upgrading to qiskit 0.45, so maybe we can just put that version in the requirements.txt?

[kt474]

Should be fixed by #736, planning on doing a release tomorrow.

[kt474]

Fixed by #736