-
Notifications
You must be signed in to change notification settings - Fork 5
/
day-16.cpp
53 lines (43 loc) · 1.34 KB
/
day-16.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
/*
Question: Given a string containing only three types of characters: '(', ')' and '*', write a function to check whether this string is valid. We define the validity of a string by these rules:
Any left parenthesis '(' must have a corresponding right parenthesis ')'.
Any right parenthesis ')' must have a corresponding left parenthesis '('.
Left parenthesis '(' must go before the corresponding right parenthesis ')'.
'*' could be treated as a single right parenthesis ')' or a single left parenthesis '(' or an empty string.
An empty string is also valid.
Example 1:
Input: "()"
Output: True
Example 2:
Input: "(*)"
Output: True
Example 3:
Input: "(*))"
Output: True
Note:
The string size will be in the range [1, 100].
*/
// O(N) & O(1) beats 100% cpp solution
class Solution {
public:
bool checkValidString(string s) {
int balance = 0;
for (int i = 0; i < s.length(); i++) {
if (s[i] == ')')
balance -= 1;
else
balance += 1;
if (balance < 0) return false;
}
if (balance == 0) return true;
balance = 0;
for (int i = s.length() - 1; i >= 0; i--) {
if (s[i] == '(')
balance -= 1;
else
balance += 1;
if (balance < 0) return false;
}
return true;
}
};