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I've noticed that the results are sensitive to scaling. If we have a time series z, maybe it is good idea to operate on (z .- mean(z)) ./ std(z), and undo the normalisation before returning? The results can be drastically different otherwise depending on the units chosen.
The text was updated successfully, but these errors were encountered:
Actually I think the results become different because of the filter initialization. We use big kappa approximation for filter initialization but there is an algorithm that performs an exact initialization of the Kalman filter.
I've noticed that the results are sensitive to scaling. If we have a time series
z
, maybe it is good idea to operate on(z .- mean(z)) ./ std(z)
, and undo the normalisation before returning? The results can be drastically different otherwise depending on the units chosen.The text was updated successfully, but these errors were encountered: