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Description

We have a string S of lowercase letters, and an integer array shifts.

Call the shift of a letter, the next letter in the alphabet, (wrapping around so that 'z' becomes 'a'). 

For example, shift('a') = 'b', shift('t') = 'u', and shift('z') = 'a'.

Now for each shifts[i] = x, we want to shift the first i+1 letters of S, x times.

Return the final string after all such shifts to S are applied.

Example 1:

Input: S = "abc", shifts = [3,5,9]

Output: "rpl"

Explanation: 

We start with "abc".

After shifting the first 1 letters of S by 3, we have "dbc".

After shifting the first 2 letters of S by 5, we have "igc".

After shifting the first 3 letters of S by 9, we have "rpl", the answer.

Note:

    <li><code>1 &lt;= S.length = shifts.length &lt;= 20000</code></li>
    
    <li><code>0 &lt;= shifts[i] &lt;= 10 ^ 9</code></li>
    

Solutions

Python3

Java

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