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86.cpp
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// Author : Accagain
// Date : 17/5/26
// Email : chenmaosen0@gmail.com
/***************************************************************************************
*
* 题意:
* Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.
*
* You should preserve the original relative order of the nodes in each of the two partitions.
*
* For example,
* Given 1->4->3->2->5->2 and x = 3,
* return 1->2->2->4->3->5.
*
* 做法:
*
* 时间复杂度:
*
*
****************************************************************************************/
#include <cstdlib>
#include <cstdio>
#include <iostream>
#include <vector>
#include <string>
#define INF 0x3fffffff
using namespace std;
struct ListNode {
int val;
ListNode *next;
ListNode(int x) : val(x), next(NULL) {}
};
class Solution {
public:
ListNode* partition(ListNode* head, int x) {
ListNode * empty = new ListNode(0);
empty->next = head;
ListNode * pre = empty;
ListNode * ans = new ListNode(0);
ListNode * p = ans;
while(head)
{
if(head->val < x)
{
p->next = new ListNode(head->val);
p = p->next;
pre->next = head->next;
head = head->next;
}
else
{
head = head->next;
pre = pre->next;
}
}
p->next = empty->next;
return ans->next;
}
};
int main() {
Solution *test = new Solution();
int data[] = {1, 4, 3, 2, 5, 2};
vector<int> x(data, data + sizeof(data) / sizeof(data[0]));
ListNode * ca = new ListNode(0);
ListNode * p = ca;
for(int i=0; i<x.size(); i++)
{
p->next = new ListNode(x[i]);
p = p->next;
}
ListNode *ans = test->partition(ca->next, 3);
while(ans)
{
printf("%d\n", ans->val);
ans = ans->next;
}
return 0;
}
//
// Created by cms on 17/5/26.
//